如何使用 setuptools 和 setup.py 从包中排除单个文件
问题描述
我正在研究 blowdrycss
.存储库在这里.
I am working on blowdrycss
. The repository is here.
我希望将 blowdrycss_settings.py
的设置文件从 pypi 的最终包中排除.目的是动态构建一个自定义设置文件,该文件将放置在用户 virtualenv/项目文件夹中.
I want the settings file for blowdrycss_settings.py
to be excluded from the final package on pypi. The intention is to dynamically build a custom settings file that will be placed in the users virtualenv / project folder.
在 setup.py
中,我有以下内容:
In setup.py
, I have the following:
packages=find_packages(exclude=['blowdrycss_settings.py', ]),
我也试过 exclude_package_data:
exclude_package_data={
'': ['blowdrycss_settings.py'],
'': ['blowdrycss/blowdrycss_settings.py'],
'blowdrycss': ['blowdrycss_settings.py'],
},
然后我运行 python setup.py sdist bdist
.
但是,当我查看构建文件夹时,我仍然看到 blowdrycss_settings.py
:
However, when I look in the build folder I still see blowdrycss_settings.py
:
- build
- lib
- blowdrycss_settings.py
似乎只排除一个文件应该很简单.
It seems like it should be simple to just exclude a file.
如何从分布式包中排除blowdrycss_settings.py
?
How do I exclude blowdrycss_settings.py
from the distributed package?
解决方案
这是我的解决方案.
在 blowdrycss
下,我创建了一个名为 settings
的新模块,因此目录结构现在如下所示:
Underneath of blowdrycss
, I created a new module called settings
so the directory structure now looks like this:
blowdrycss
blowdrycss
settings
blowdrycss_settings.py
基于此参考,在setup.py
我有以下内容:
Based on this reference, inside of setup.py
I have the following:
packages=find_packages(exclude=['*.settings', ]),
构建发行版:
- 删除
build
、dist
和.egg-info
文件夹. - 运行
python setup.py sdist bdist
- Delete the
build
,dist
, and.egg-info
folders. - Run
python setup.py sdist bdist
回想起来,我无法做我最初尝试的事情是件好事.新结构感觉更干净,更模块化.
In retrospect, it is good that I was unable to do what I was originally attempting. The new structure feels cleaner and is more modular.
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