在unicode字符串中转换字节字符串
问题描述
我有这样的代码:
a = "u0432"
b = u"u0432"
c = b"u0432"
d = c.decode('utf8')
print(type(a), a)
print(type(b), b)
print(type(c), c)
print(type(d), d)
然后输出:
<class 'str'> в
<class 'str'> в
<class 'bytes'> b'\u0432'
<class 'str'> u0432
为什么在后一种情况下我看到的是字符代码，而不是字符?如何将 Byte 字符串转换为 Unicode 字符串，以便在输出时我看到的是字符而不是其代码?
Why in the latter case I see a character code, instead of the character? How I can transform Byte string to Unicode string that in case of an output I saw the character, instead of its code?
解决方案
在字符串(或 Python 2 中的 Unicode 对象)中，u 有一个特殊的含义，即这里来了一个 Unicode由它的 Unicode ID 指定的字符".因此 u"u0432" 将产生字符 в.
In strings (or Unicode objects in Python 2), u has a special meaning, namely saying, "here comes a Unicode character specified by it's Unicode ID". Hence u"u0432" will result in the character в.
b'' 前缀告诉你这是一个 8 位字节序列，并且 bytes 对象没有 Unicode 字符，所以 u 代码没有特殊意义.因此，b"u0432" 只是字节的序列 ,u,0,4、3 和 2.
The b'' prefix tells you this is a sequence of 8-bit bytes, and bytes object has no Unicode characters, so the u code has no special meaning. Hence, b"u0432" is just the sequence of the bytes ,u,0,4,3 and 2.
本质上，您有一个 8 位字符串，其中不包含 Unicode 字符，而是包含 Unicode 字符的规范.
Essentially you have an 8-bit string containing not a Unicode character, but the specification of a Unicode character.
您可以使用 unicode 转义编码器转换此规范.
You can convert this specification using the unicode escape encoder.
>>> c.decode('unicode_escape')
'в'
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