pi 计算中的分段错误(python)
问题描述
def pi(times):
seq = []
counter = 0
for x in range(times):
counter += 2
seq.append("((%f**2)/(%f*%f))*"%(float(counter), float(counter-1), float(counter+1)))
seq.append("1.0")
seq = "".join(seq)
seq = eval(seq)
return seq*2
在超过 85000 个术语的任何地方,我都会遇到分段错误并且 python 退出.我怎样才能避免这种情况?为什么会崩溃?就不能请使用更多的内存或其他东西吗?
Anywhere past 85000 terms I get a segmentation fault and python quits. How can I avoid this? Why is it crashing? Can't it just please use more memory or something?
解决方案
您似乎在 eval
中发现了一个错误,它无法处理超长的表达式:
You appear to have found a bug in eval
where it can't handle insanely long expressions:
>>> eval("1.0*"*10000+"1.0")
1.0
>>> eval("1.0*"*100000+"1.0")
# segfault here
不过,我还是明智地使用了非常长"这个短语.不要那样做,边走边计算.在这种情况下没有理由使用 eval
.
I use the phrase "insanely long" advisedly though. Don't do it that way, calculate the pieces as you go. There is no reason to be using eval
in this situation.
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