参数 1 有意外的类型“NoneType"?

2022-01-12 00:00:00 python pyqt5

问题描述

我的 PyQt 按钮操作有问题.我想发送一个带有函数的字符串，但我收到了这个错误:

I have a problem with my PyQt button action. I would like to send a String with the Function but I got this Error:

TypeError:参数 1 具有意外类型NoneType"

TypeError: argument 1 has unexpected type 'NoneType'

import sys

from PyQt5.QtWidgets import QApplication, QPushButton, QAction
from PyQt5.QtCore import QObject, pyqtSignal
from PyQt5.QtGui import *
from PyQt5.uic import *

app = QApplication(sys.argv)
cocktail = loadUi('create.ui')

def mixCocktail(str):
      cocktail.show()
      cocktail.showFullScreen()
      cocktail.lbl_header.setText(str)


widget = loadUi('drinkmixer.ui')

widget.btn_ckt1.clicked.connect(mixCocktail("string"))

widget.show()
sys.exit(app.exec_())

解决方案

根据 user3030010 和 ekhumoro 它需要一个可调用的函数.在这种情况下，您应该将该参数替换为 lambda: mixCocktail("string")AND ALSO 不要使用 str 它是 python 内置数据类型，我已将其替换为 _str

As suggested by user3030010 and ekhumoro it expects a callable function. In which case you should replace that argument with lambda: mixCocktail("string") AND ALSO don't use str it's a python built-in datatype I have replaced it with _str

import sys

from PyQt5.QtWidgets import QApplication, QPushButton, QAction
from PyQt5.QtCore import QObject, pyqtSignal
from PyQt5.QtGui import *
from PyQt5.uic import *

app = QApplication(sys.argv)
cocktail = loadUi('create.ui')

def mixCocktail(_str):
      cocktail.show()
      cocktail.showFullScreen()
      cocktail.lbl_header.setText(_str)
      

widget = loadUi('drinkmixer.ui')

widget.btn_ckt1.clicked.connect(lambda: mixCocktail("string"))

widget.show()
sys.exit(app.exec_())

关于 lambda 函数的更多信息:什么是 lambda(函数)?

More about lambda functions: What is a lambda (function)?

相关文章