带有工作进程的 python 池
问题描述
我正在尝试使用进程对象在 python 中使用工作池.每个工人(一个进程)进行一些初始化(花费大量时间)，传递一系列作业(理想情况下使用 map())，并返回一些东西.除此之外，不需要任何沟通.但是，我似乎无法弄清楚如何使用 map() 来使用我的工人的 compute() 函数.
I am trying to use a worker Pool in python using Process objects. Each worker (a Process) does some initialization (takes a non-trivial amount of time), gets passed a series of jobs (ideally using map()), and returns something. No communication is necessary beyond that. However, I can't seem to figure out how to use map() to use my worker's compute() function.
from multiprocessing import Pool, Process
class Worker(Process):
def __init__(self):
print 'Worker started'
# do some initialization here
super(Worker, self).__init__()
def compute(self, data):
print 'Computing things!'
return data * data
if __name__ == '__main__':
# This works fine
worker = Worker()
print worker.compute(3)
# workers get initialized fine
pool = Pool(processes = 4,
initializer = Worker)
data = range(10)
# How to use my worker pool?
result = pool.map(compute, data)
是作业队列代替，还是我可以使用 map()?
Is a job queue the way to go instead, or can I use map()?
解决方案
我建议你为此使用队列.
I would suggest that you use a Queue for this.
class Worker(Process):
def __init__(self, queue):
super(Worker, self).__init__()
self.queue = queue
def run(self):
print('Worker started')
# do some initialization here
print('Computing things!')
for data in iter(self.queue.get, None):
# Use data
现在您可以开始一堆这些，所有这些都从一个队列中获取工作
Now you can start a pile of these, all getting work from a single queue
request_queue = Queue()
for i in range(4):
Worker(request_queue).start()
for data in the_real_source:
request_queue.put(data)
# Sentinel objects to allow clean shutdown: 1 per worker.
for i in range(4):
request_queue.put(None)
这样的事情应该可以让您将昂贵的启动成本分摊给多个工人.
That kind of thing should allow you to amortize the expensive startup cost across multiple workers.
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