如何将变量设置为“今天的"?Python/Pandas 中的日期
问题描述
我正在尝试将变量设置为今天的日期.
I am trying to set a variable to equal today's date.
我查了一下,找到了一篇相关的文章:
I looked this up and found a related article:
将今天的日期设置为模型中的默认值一个>
但是,这并没有特别回答我的问题.
However, this didn't particularly answer my question.
我使用了建议的:
dt.date.today
但是之后
import datetime as dt
date = dt.date.today
print date
<built-in method today of type object at 0x000000001E2658B0>
Df['Date'] = date
我没有得到我真正想要的作为今天日期的干净日期格式......月/日/年.
I didn't get what I actually wanted which as a clean date format of today's date...in Month/Day/Year.
如何创建今天的变量,以便在 DataFrame 中输入该变量?
How can I create a variable of today's day in order for me to input that variable in a DataFrame?
解决方案
你提到你正在使用 Pandas(在你的标题中).如果是这样,则无需使用外部库,您可以使用 to_datetime
You mention you are using Pandas (in your title). If so, there is no need to use an external library, you can just use to_datetime
>>> pandas.to_datetime('today').normalize()
Timestamp('2015-10-14 00:00:00')
无论实际时间如何,这总是会在午夜返回今天的日期,并且可以直接在 pandas 中用于进行比较等.Pandas 的日期时间中总是包含 00:00:00.
This will always return today's date at midnight, irrespective of the actual time, and can be directly used in pandas to do comparisons etc. Pandas always includes 00:00:00 in its datetimes.
将 today
替换为 now
将为您提供 UTC 日期而不是本地时间;请注意,在这两种情况下都不会添加 tzinfo(时区).
Replacing today
with now
would give you the date in UTC instead of local time; note that in neither case is the tzinfo (timezone) added.
在 0.23.x 之前的 pandas 版本中,可能不需要 normalize
来删除非午夜时间戳.
In pandas versions prior to 0.23.x, normalize
may not have been necessary to remove the non-midnight timestamp.
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