Python:os.path.isfile 无法识别以数字开头的文件
问题描述
所以,我正在尝试将 os.path.isfile
或 os.path.exists
合并到我的代码中,并成功找到某些常规文件(pdf,png) 搜索以字母开头的文件名时.
So, I'm trying to incorporate os.path.isfile
or os.path.exists
into my code with success in finding certain regular files(pdf,png) when searching for filenames that begin with a letter.
我正在使用的文件命名标准(并且由于用户而无法更改)以数字开头,随后无法使用相同的方法找到.有没有办法让 .isfile
或 .exists
发现这些文件?
The file naming standard that I'm using (and can't change due to the user) starts with a number and subsequently can't be found using the same method. Is there a way that I can make these files discoverable by .isfile
or .exists
?
我要搜索的文件是 .txt 文件.
The files I'm searching for are .txt files.
os.path.isfile("D:Usersspx9gsProject WorkData21022013AA.txt")
os.path.isfile("D:Usersspx9gsProject WorkDataAA21022013.txt")
返回:
错误
是的
解决方案
你需要使用原始字符串,或者转义你的反斜杠.在文件名中:
You need to use raw strings, or escape your backslashes. In the filename:
"D:Usersspx9gsProject WorkData21022013AA.txt"
210
将被解释为八进制转义码,因此您将无法获得正确的文件名.
the 210
will be interpreted as an octal escape code so you won't get the correct filename.
以下任何一种都可以:
r"D:Usersspx9gsProject WorkData21022013AA.txt"
"D:\Users\spx9gs\Project Work\Data\21022013AA.txt"
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