如何按目录文件名中的数字对文件进行排序?
问题描述
我有一个目录，其中包含许多按特定顺序命名的文本文件:
I have a directory containing a lot of textfiles named in a specific order:
0.txt
1.txt
2.txt
....
100.txt
101.txt
.....
40000.txt
当我试图检索我正在使用的所有文件的排序列表时:
When im trying to retrieve a sorted list of all the files im using:
for file in sorted(os.listdir(filepath)):
print(file)
我得到的结果是:
0.txt
1.txt
10.txt
100.txt
1000.txt
10000.txt
10001.txt
10002.txt
10003.txt
10004.txt
.....
这不是我想要的，我想要它按正常的升序排列:
Which is not how i want it, i want it in normal ascending order:
0.txt
1.txt
2.txt
3.txt
4.txt
...
有人知道怎么做吗?
解决方案
可以使用 lambda 表达式
Could use a lambda expression
import os
filelist = os.listdir(path)
filelist = sorted(filelist,key=lambda x: int(os.path.splitext(x)[0]))
for file in filelist:
print(file)
输出为:
1.txt
2.txt
3.txt
4.txt
5.txt
6.txt
7.txt
8.txt
9.txt
10.txt
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