在 python 中仅提取电子邮件标头

2022-01-11 00:00:00 python email header

问题描述

我在尝试在 python 中提取所有电子邮件标头时遇到了一些问题.我知道如何获取我正在寻找的那些，但我想保存所有标题，但我不知道该怎么做.

I'm having some issues trying to extract all the email headers in python. I know how to get the ones I'm looking for but I want to save all the headers and I'm not sure how to do that.

我已将其加载到电子邮件对象中

I have it loaded into a email object

import email
f = open(kwargs['opt_emailfile'])
msg = email.message_from_file(f)
f.close()

所以我可以得到

msg['To']
msg['From']

但我想要所有的标题

解决方案

感谢回答，这是我所做的

Here is what I did thanks to the answer

        f = open(kwargs['opt_emailfile'])
        msg = email.message_from_file(f)
        f.close()

        parser = email.parser.HeaderParser()
        headers = parser.parsestr(msg.as_string())

        for h in headers.items():
            print h

解决方案

使用 HeaderParser 或许:

from email.parser import HeaderParser
parser = HeaderParser()
h = parser.parsestr(email)

print h.keys()

我刚刚注意到您编辑了您的问题.您实际上可以在不使用 HeaderParser 的情况下从您所拥有的信息中获得相同的信息.例如headers.items() 将返回带有标题和相应值的 2 元组列表.

I just noticed you edited your question. You can actually get the same information from what you had without using HeaderParser. e.g. headers.items() will return list of 2-tuples with headers and corresponding values.

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