如何向 urllib2 开启程序添加标题?

2022-01-11 00:00:00 python http urllib2 header

问题描述

cj = cookielib.CookieJar()opener = urllib2.build_opener(urllib2.HTTPCookieProcessor(cj))opener.open('http://abc.com')opener.open('http://google.com')

如您所见,我使用 opener 访问不同的网站,使用 cookie jar.我可以设置一个标头,以便每次访问网站时都应用标头吗?

解决方案

你可以直接将headers添加到build_opener返回的OpenerDirector对象.从 urllib2 docs 中的最后一个示例:

<块引用>

OpenerDirector 会自动为每个请求添加一个 User-Agent 标头.要改变这一点:

导入urllib2opener = urllib2.build_opener()opener.addheaders = [('用户代理', 'Mozilla/5.0')]opener.open('http://www.example.com/')

<块引用>

另外,请记住,在将请求传递给 urlopen()(或 OpenerDirector.open())时会添加一些标准标头(Content-Length、Content-Type 和 Host).

cj = cookielib.CookieJar()
opener = urllib2.build_opener(urllib2.HTTPCookieProcessor(cj))    
opener.open('http://abc.com')
opener.open('http://google.com')

As you can see, I use opener to visit different websites, using a cookie jar. Can I set a header so that each time a website is it, the header is applied?

解决方案

You can add the headers directly to the OpenerDirector object returned by build_opener. From the last example in the urllib2 docs:

OpenerDirector automatically adds a User-Agent header to every Request. To change this:

import urllib2
opener = urllib2.build_opener()
opener.addheaders = [('User-agent', 'Mozilla/5.0')]
opener.open('http://www.example.com/')

Also, remember that a few standard headers (Content-Length, Content-Type and Host) are added when the Request is passed to urlopen() (or OpenerDirector.open()).

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