有没有办法将 24 小时时间格式转换为一天的四个类别或四个象限?

2022-01-11 00:00:00 python python-3.x pandas time-series

问题描述

我正在尝试将数据中的时间戳预处理为一天中的四个类别.

I am trying to pre-process timestamp in my data into four categories of the day.

这意味着我需要将对象数据类型转换为类别

This means i need to convert object data type to categories namely

早上 00:00:00 到 11:59:59

Morning for 00:00:00 to 11:59:59

下午 12:00:00 至 15:59:59

Afternoon for 12:00:00 to 15:59:59

晚上 16:00:00 至 19:59:59

Evening for 16:00:00 to 19:59:59

晚上 20:00:00 至 23:59:59

Night for 20:00:00 to 23:59:59

我的时间戳数据看起来像

my timestamp data looks like

transaction timestamp 08:26:00 08:26:00 08:26:00 08:26:00 12:26:00 12:45:00 16:26:00 16:28:00 20:28:00 20:34:00

我希望上述列的输出为

time of day Morning Morning Morning Morning Afternoon Afternoon Evening Evening Night Night

我应该如何清理这种类型的数据并将其转换为仅 4 个类别?

How shall i clean this type of data and convert it to just 4 categories?

解决方案

您可以通过 to_timedelta 然后使用 cut:

You can convert values to timedeltas by to_timedelta and then use cut:

df['transaction timestamp'] = pd.to_timedelta(df['transaction timestamp']) #if values are python object times convert to strings #df['transaction timestamp'] = pd.to_timedelta(df['transaction timestamp'].astype(str)) b = pd.to_timedelta(['00:00:00','12:00:00','16:00:00','20:00:00', '24:00:00']) l = ['Morning','Afternoon','Evening','Night'] df['time of day'] = pd.cut(df['transaction timestamp'], bins=b, labels=l) print (df) transaction timestamp time of day 0 08:26:00 Morning 1 08:26:00 Morning 2 08:26:00 Morning 3 08:26:00 Morning 4 12:26:00 Afternoon 5 12:45:00 Afternoon 6 16:26:00 Evening 7 16:28:00 Evening 8 20:28:00 Night 9 20:34:00 Night

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