在 Python 中生成日期到一周中的几天?
问题描述
我需要从某个日期(例如:2015/10/22)生成一周中的星期一的日期.并生成接下来几天的日期:周一、周二、周三、周四、周五、周六、周日.
I need to generate a date of Monday of a week from a date (example: 2015/10/22). And generate the dates for the next days: Monday, Tuesday, Wednesday, Thursday, Friday, Saturday, Sunday.
Java 中的示例:(初始日期 = 2015/10/22)
Example in Java: (initial date = 2015/10/22)
//星期一:
date.set (Calendar.DAY_OF_WEEK, Calendar.MONDAY);
//添加第二天(星期二)
// Add the next day (Tuesday)
date.add (Calendar.DATE, 1);
//添加第二天(星期三):
// Add the next day (Wednesday):
date.add (Calendar.DATE, 1);
如何在 Python 中做到这一点?
How can I do this in Python?
解决方案
在python中使用timedelta函数更简单
Its easier in python using timedelta function
import datetime
mydate = datetime.datetime(2015, 10, 22, 00, 00, 00, 00)
mymondaydate = mydate - datetime.timedelta(days=mydate.weekday())
mytuesdaydate = mymondaydate + datetime.timedelta(days=1)
print(mydate)
print(mymondaydate)
print(mytuesdaydate)
诀窍是使用 weekday() 函数.来自文档
The trick is the use of weekday() function. From documentation
date.weekday()- 以整数形式返回星期几，其中星期一为 0，星期日为 6.
date.weekday() - Return the day of the week as an integer, where Monday is 0 and Sunday is 6.
所以从当前日期中减去它得到该周的星期一的日期
So subtracting it from current date gives the date of Monday of that week
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