如何获取 Python 中两个 xml 标签之间的全部内容?
问题描述
我尝试获取打开的 xml 标记和它的关闭对应项之间的全部内容.
I try to get the whole content between an opening xml tag and it's closing counterpart.
像下面的 title
这样直接获取内容很容易,但是如果 mixed-content 被使用,我想保留内部标签?
Getting the content in straight cases like title
below is easy, but how can I get the whole content between the tags if mixed-content is used and I want to preserve the inner tags?
<?xml version="1.0" encoding="UTF-8"?>
<review>
<title>Some testing stuff</title>
<text sometimes="attribute">Some text with <extradata>data</extradata> in it.
It spans <sometag>multiple lines: <tag>one</tag>, <tag>two</tag>
or more</sometag>.</text>
</review>
我想要的是两个text
标签之间的内容,包括任何标签:Some text with <extradata>data</extradata>在里面.它跨越<sometag>多行:<tag>one</tag>、<tag>two</tag>或更多</sometag>.
现在我使用正则表达式,但它有点乱,我不喜欢这种方法.我倾向于基于 XML 解析器的解决方案.我查看了 minidom
、etree
、lxml
和 BeautifulSoup
,但找不到适合这种情况的解决方案(整个内容,包括内部标签).
For now I use regular expressions but it get's kinda messy and I don't like this approach. I lean towards a XML parser based solution. I looked over minidom
, etree
, lxml
and BeautifulSoup
but couldn't find a solution for this case (whole content, including inner tags).
解决方案
from lxml import etree
t = etree.XML(
"""<?xml version="1.0" encoding="UTF-8"?>
<review>
<title>Some testing stuff</title>
<text>Some text with <extradata>data</extradata> in it.</text>
</review>"""
)
(t.text + ''.join(map(etree.tostring, t))).strip()
这里的诀窍是 t
是可迭代的,并且在迭代时会产生所有子节点.因为etree避免了文本节点,所以还需要恢复第一个子标签之前的文本,用t.text
.
The trick here is that t
is iterable, and when iterated, yields all child nodes. Because etree avoids text nodes, you also need to recover the text before the first child tag, with t.text
.
In [50]: (t.text + ''.join(map(etree.tostring, t))).strip()
Out[50]: '<title>Some testing stuff</title>
<text>Some text with <extradata>data</extradata> in it.</text>'
或者:
In [6]: e = t.xpath('//text')[0]
In [7]: (e.text + ''.join(map(etree.tostring, e))).strip()
Out[7]: 'Some text with <extradata>data</extradata> in it.'
相关文章