使用 Python 2 在 XML 中按属性查找所有节点

2022-01-10 00:00:00 python python-2.7 xml xml-parsing

问题描述

我有一个 XML 文件,其中包含许多具有相同属性的不同节点.

I have an XML file which has a lot of different nodes with the same attribute.

我想知道是否可以使用 Python 和任何其他包(如 minidom 或 ElementTree)找到所有这些节点.

I was wondering if it's possible to find all these nodes using Python and any additional package like minidom or ElementTree.


解决方案

可以使用内置的xml.etree.ElementTree 模块.

You can use built-in xml.etree.ElementTree module.

如果您希望所有元素都具有特定属性而不考虑属性值,则可以使用 xpath 表达式:

If you want all elements that have a particular attribute regardless of the attribute values, you can use an xpath expression:

//tag[@attr]

或者,如果您关心价值观:

Or, if you care about values:

//tag[@attr="value"]

示例(使用 <代码>findall() 方法):

Example (using findall() method):

import xml.etree.ElementTree as ET

data = """
<parent>
    <child attr="test">1</child>
    <child attr="something else">2</child>
    <child other_attr="other">3</child>
    <child>4</child>
    <child attr="test">5</child>
</parent>
"""

parent = ET.fromstring(data)
print [child.text for child in parent.findall('.//child[@attr]')]
print [child.text for child in parent.findall('.//child[@attr="test"]')]

打印:

['1', '2', '5']
['1', '5']

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