返回剩余的Tweepy点击数

问题描述

编辑：我正在尝试以下代码，以便读取ID列表并获取它们的对应名称。我正在尝试使用reamin_search_limits，以避免Rate_Limit错误。

limits = api.rate_limit_status()
remain_search_limits = limits['resources']['search']['/search/tweets']['remaining']
stream = open('myfile','w')
ss     = open('userNames', 'w')
for ids in content:
try:
    limits = api.rate_limit_status()
    remain_search_limits = limits['resources']['search']['/search/tweets']['remaining']
    print 'you have', remain_search_limits, 'API calls remaining until next hour'
    if remain_search_limits < 2:
         dtcode = datetime.utcnow()
         unixtime = calendar.timegm(dtcode.utctimetuple())
         sleeptime = rate_limit_json.get('reset_time_in_seconds') - unixtime + 10
         print 'waiting ', sleeptime, 'seconds'
         sleep(sleeptime)
    else:
         user = api.get_user(ids) 
         stream.write(str(user.id)+"
")
         ss.write(str(user.name)+"
")
except (tweepy.TweepError) as e:
    print e 
    stream.close()
    ss.close()

每次打印RESTAIN_SEARCH_LIMITS时返回180，直到出现tweepError异常。

---

解决方案

此示例显示如何访问剩余的tweet数量。

print rate_limit_json["resources"]["search"]['/search/tweets']['remaining']
180

"resources" is the key you should be using to access the information inside.

如果您要更新值，请将其放入循环中，并在计时后重新赋值。睡眠()。

将所有代码放在一个While循环中： 大概是这样的：

limits = api.rate_limit_status()
remain_search_limits = limits['resources']['search']['/search/tweets']['remaining']
while remain_search_limits >2:
  limits = api.rate_limit_status()
  remain_search_limits = limits['resources']['search']['/search/tweets']['remaining']
else:
   dtcode = datetime.utcnow()
   unixtime = calendar.timegm(dtcode.utctimetuple())
   sleeptime = rate_limit_json.get('reset_time_in_seconds') - unixtime + 10
   print 'waiting ', sleeptime, 'seconds'
   sleep(sleeptime)

我尚未测试代码，但它应该接近您需要的内容。

您可能希望在两次调用之间休眠，我不熟悉该API，因此不确定您到底在做什么。