Pandas - 有条件的删除重复项
问题描述
我有一个适用于 Python 3.6x 的 Pandas 0.19.2 数据框,如下所示.我想基于条件逻辑使用相同的 Id
drop_duplicates()
.
I have a Pandas 0.19.2 dataframe for Python 3.6x as below. I want to drop_duplicates()
with the same Id
based on a conditional logic.
import pandas as pd
import numpy as np
np.random.seed(1)
df = pd.DataFrame({'Id':[1,2,3,4,3,2,6,7,1,8],
'Name':['A', 'B', 'C', 'D', 'E', 'F', 'G', 'H', 'I', 'K'],
'Size':np.random.rand(10),
'Age':[19, 25, 22, 31, 43, 23, 44, 20, 51, 31]})
根据我在下面描述的逻辑,实现这一目标的最有效(如果可能的话)方法是什么?
What would be the most efficient (if possible vectorised) way to achieve this based on the logic I describe below?
1) 在删除重复项之前,将重复的 Id
条目的 Size
相加.
1) Before dropping duplicates, sum the Size
of duplicate Id
entries.
2) 删除相同 Id
记录的重复记录,保留具有较大 Age
记录的记录.
2) Drop duplicates for same Id
records, keeping the one that has a larger Age
.
期望的输出是:
Age Id Name Size
1 25 2 B 0.812662
3 31 4 D 0.302333
4 43 3 E 0.146870
6 44 6 G 0.186260
7 20 7 H 0.345561
8 51 1 I 0.813790
9 31 8 K 0.538817
解决方案
使用GroupBy.transform
用于与 sort_values
和 drop_duplicates
用于删除重复:
Use GroupBy.transform
for aggregated values with same size as original DataFrame with sort_values
and drop_duplicates
for remove dupes:
df['Size'] = df.groupby('Id')['Size'].transform('sum')
df = df.sort_values('Age').drop_duplicates('Id', keep='last').sort_index()
print (df)
Id Name Size Age
1 2 B 0.812663 25
3 4 D 0.302333 31
4 3 E 0.146870 43
6 6 G 0.186260 44
7 7 H 0.345561 20
8 1 I 0.813789 51
9 8 K 0.538817 31
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