在 Python 的列表中保留重复项
问题描述
我知道这可能是一个简单的答案，但我想不通.Python中将重复项保存在列表中的最佳方法是什么:
I know this is probably an easy answer but I can't figure it out. What is the best way in Python to keep the duplicates in a list:
x = [1,2,2,2,3,4,5,6,6,7]
输出应该是:
[2,6]
我找到了这个链接:查找(并保留)子列表的重复项在 python 中，但我对 Python 还是比较陌生，我不能让它为一个简单的列表工作.
I found this link: Find (and keep) duplicates of sublist in python, but I'm still relatively new to Python and I can't get it to work for a simple list.
解决方案
如果列表已经排序，这是一个简单的方法:
This is a short way to do it if the list is sorted already:
x = [1,2,2,2,3,4,5,6,6,7]
from itertools import groupby
print [key for key,group in groupby(x) if len(list(group)) > 1]
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