如何在网站 selenium 上显示错误消息时打印消息

2022-01-10 00:00:00 python selenium xpath css-selectors webdriverwait

问题描述

您好，我正在尝试使用 selenium 抓取网站，但有时该网站会阻止我的 ip 进行抓取并出现弹出消息.

Hi I am trying to scrape a website using selenium after sometime the website blocks my ip for scraping and a pop up message appears.

我想要做的是，每当弹出消息出现时，它都会在我的终端上显示一个警告，我的代码看起来像这样以获得结果

What i want to do is that whenever that pop up message appear it displays a warning on my terminal, My code looks like this to get the result 

blo = driver.find_element_by_xpath('/html/body/div[2]/div/div/div[1]/h3')
if blo:
    print('ip blocked')
else:
    print('eroor')

但它不工作我只是得到一个空白屏幕，我该如何解决这个问题

But its not working i just get a blank screen, How can i solve this

元素的HTML:

<h3 class="modal-title">Notifications</h3>
<div class="alert alert-warning">Sorry, you have exceeded the maximum number of queries allowed per day. If you believe you have reached this message in error, please contact our support team.</div>

解决方案

验证 弹出消息 你必须为 诱导 WebDriverWaitvisibility_of_element_located() 并且您可以使用以下任一 Locator策略:

The validate the presence of the pop up message you have to induce WebDriverWait for the visibility_of_element_located() and you can use either of the following Locator Strategies:

  • 使用 CSS_SELECTOR:

try:
    WebDriverWait(driver, 20).until(EC.visibility_of_element_located((By.XPATH, "h3.modal-title+div.alert.alert-warning")))
    print("ip blocked")
except TimeoutException:
    print("eroor")

  • 使用 XPATH:

    try:
    WebDriverWait(driver, 20).until(EC.visibility_of_element_located((By.XPATH, "//h3[@class='modal-title' and text()='Notifications']//following::div[@class='alert alert-warning']")))
    print("ip blocked")
except TimeoutException:
    print("eroor")

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