如何在python中将二进制字符串转换为ascii字符串?
问题描述
我制作了一个小 Python 程序,它从文件中读取二进制文件并将其存储到文本文件中,读取文本文件并存储二进制文件.但是,我无法让二进制文件工作......它像这样读取文件:
I've made a little python program that reads binary from a file and stores it to a text file, read the text file and store the binary. But, I can't get the binary to work... it reads the files like this:
f_bin = open(bin_file,"rb")
to_bin_data = f_bin.read()
bin_data = bin(reduce(lambda x, y: 256*x+y, (ord(c) for c in to_bin_data), 0))
f_bin.close()
这个对我不起作用... 将二进制转换为ASCII,反之亦然
类似这个网页:http://www.roubaixinteractive.com/PlayGround/Binary_Conversion/Binary_To_Text.asp
我现在为它制作了一个很长的 if else 脚本,但感谢您的回答
解决方案
我们来看看'hello'这个词,它是0110100001100101011011000110110001101111
Let's take the word 'hello' which is 0110100001100101011011000110110001101111
要将其转换回字符,我们可以使用 chr
和 int
(以 2 为基数)以及一些列表切片...
To translate that back to characters we can use chr
and int
(with a base of 2) and some list slicing...
''.join(chr(int(bin_text[i:i+8], 2)) for i in xrange(0, len(bin_text), 8))
如果我们想将 'hello' 转换为二进制,我们可以使用 ord
和字符串格式化...
If we wanted to take 'hello' and convert it to binary we can use ord
and string formatting...
''.join('{:08b}'.format(ord(c)) for c in 'hello')
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