N个列表元素的总和python
问题描述
有没有一种简单的方法来计算 Python 中 N 个列表的元素总和?我知道如果我们有n个列表定义(调用第i个列表c_i)，我们可以这样做:
Is there an easy way to compute the element-wise sum of N lists in python? I know if we have n lists defined (call the ith list c_i), we can do:
z = [sum(x) for x in zip(c_1, c_2, ...)]
例如:
c1 = [1,2]
c2 = [3,4]
c3 = [5,6]
z = [sum(x) for x in zip(c1,c2,c3)]
这里z = [9, 12]
但是如果我们没有定义 c_i 而是在列表 C 中有 c_1...c_n 怎么办?
But what if we don't have c_i defined and instead have c_1...c_n in a list C?
如果我们只有 C，有没有类似的方法可以找到 z?
Is there a similar way to find z if we just have C?
我希望这很清楚.
已解决:我想知道 * 运算符是什么意思...谢谢！
resolved: I was wondering what the * operator was all about...thanks!
解决方案
这样做:
[sum(x) for x in zip(*C)]
在上面，C是c_1...c_n的列表.正如评论中的 链接 中所述(感谢@kevinsa5！):
In the above, C is the list of c_1...c_n. As explained in the link in the comments (thanks, @kevinsa5!):
* 是splat"运算符:它将一个列表作为输入，并将其扩展为函数调用中的实际位置参数.
*is the "splat" operator: It takes a list as input, and expands it into actual positional arguments in the function call.
有关更多详细信息，请查看 文档，在解包参数列表"下，还阅读了有关 调用 (谢谢@abarnert！)
For additional details, take a look at the documentation, under "unpacking argument lists" and also read about calls (thanks, @abarnert!)
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