list extend() 索引，不仅将列表元素插入到末尾
问题描述
我正在寻找最 Pythonic 的方式来实现列表 extend 函数的一个版本，它扩展到给定的索引而不是列表的末尾.
I'm looking for the most pythonic way to implement a version of the list extend function, where it extends to a given index instead of the end of the list.
a_list = [ "I", "rad", "list" ]
b_list = [ "am", "a" ]
a_list.my_extend( b_list, 1 ) # insert the items from b_list into a_list at index 1
print( a_list ) # would output: ['I', 'am', 'a', 'rad', 'list']
有没有办法在不建立新列表的情况下做到这一点，像这样?
Is there a way to do this without building a new list, like this?
a_list = [ "I", "rad", "list" ]
b_list = [ "am", "a" ]
c_list = []
c_list.extend( a_list[:1] )
c_list.extend( b_list )
c_list.extend( a_list[1:] )
print( c_list ) # outputs: ['I', 'am', 'a', 'rad', 'list']
这种方法实际上并没有那么糟糕，但我有一种预感，它可能会更容易.可以吗?
That approach isn't actually so bad, but I have a hunch it could be easier. Could it?
解决方案
当然可以使用切片索引:
Sure, you can use slice indexing:
a_list[1:1] = b_list
为了演示一般算法，如果您要在假设的自定义 list 类中实现 my_extend 函数，它看起来像这样:
Just to demonstrate the general algorithm, if you were to implement the my_extend function in a hypothetical custom list class, it would look like this:
def my_extend(self, other_list, index):
self[index:index] = other_list
但实际上不要让它成为一个函数，只需在需要时使用切片符号即可.
But don't actually make that a function, just use the slice notation when you need to.
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